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2.9 Summary

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2.9 Summary

  1. A resistor is a passi ve element in which the v oltage v across it is directly proportional to the current i through it. That is, a resistor is a device that obeys Ohm’s law,

v = iR

where R is the resistance of the resistor.

    1. A short circuit is a resistor (a perfectly , conducting wire) with zero resistance (R = 0). An open circuit is a resistor with infinite resistance (R = ∞).
    1. The conductance G of a resistor is the reciprocal of its resistance:
G=1RG = \frac{1}{R}
  1. A branch is a single tw o-terminal element in an electric circuit. A node is the point of connection between tw o or more branches. A loop is a closed path in a circuit. The number of branches b, the number of nodes n, and the number of independent loops l in a network are related as
b=l+n−1b = l + n - 1
    1. Kirchhoff’s current law (KCL) states that the currents at an y node algebraically sum to zero. In other w ords, the sum of the currents entering a node equals the sum of currents leaving the node.
    1. Kirchhoff’s v oltage la w (KVL) states that the v oltages around a closed path algebraically sum to zero. In other w ords, the sum of voltage rises equals the sum of voltage drops.
    1. Two elements are in series when the y are connected sequentially , end to end. When elements are in series, the same current flows through them (i1 = i2). They are in parallel if the y are connected to the same two nodes. Elements in parallel always have the same voltage across them (v1 = v2).
    1. When two resistors R1 (=1/G1) and R2 (=1/G2) are in series, their equivalent resistance Req and equivalent conductance Geq are
Req=R1+R2,R_{\text{eq}} = R_1 + R_2,

Geq=G1G2G1+G2G_{\text{eq}} = \frac{G_1 G_2}{G_1 + G_2}

  1. When two resistors R1 (=1/G1) and R2 (=1/G2) are in parallel, their equivalent resistance Req and equivalent conductance Geq are
Req=R1R2R1+R2,Geq=G1+G2R_{\text{eq}} = \frac{R_1 R_2}{R_1 + R_2}, \qquad G_{\text{eq}} = G_1 + G_2

Practice Problem 2.17

10. The voltage division principle for two resistors in series is

v1=R1R1+R2vv_1 = \frac{R_1}{R_1 + R_2} v

, v2=R2R1+R2vv_2 = \frac{R_2}{R_1 + R_2} v

  1. The current division principle for two resistors in parallel is
i1=R2R1+R2ii_1 = \frac{R_2}{R_1 + R_2} i

, i2=R1R1+R2ii_2 = \frac{R_1}{R_1 + R_2} i

  1. The formulas for a delta-to-wye transformation are
R1=RbRcRa+Rb+Rc,R2=RcRaRa+Rb+RcR_1 = \frac{R_b R_c}{R_a + R_b + R_c}, \qquad R_2 = \frac{R_c R_a}{R_a + R_b + R_c} R3=RaRbRa+Rb+RcR_3 = \frac{R_a R_b}{R_a + R_b + R_c}
  1. The formulas for a wye-to-delta transformation are

The formulas for a wye-to-delta transformation are
\n

Ra=R1R2+R2R3+R3R1R1,Rb=R1R2+R2R3+R3R1R2R_a = \frac{R_1 R_2 + R_2 R_3 + R_3 R_1}{R_1}, \qquad R_b = \frac{R_1 R_2 + R_2 R_3 + R_3 R_1}{R_2}

\n

Rc=R1R2+R2R3+R3R1R3R_c = \frac{R_1 R_2 + R_2 R_3 + R_3 R_1}{R_3}
  1. The basic laws covered in this chapter can be applied to the problems of electrical lighting and design of dc meters.

Review Questions

2.1The reciprocal of resistance is:
(a) voltage(b) current
(c) conductance(d) coulombs

2.2 An electric heater draws 10 A from a 120-V line. The resistance of the heater is:

(a) 1200 ÎĐ(b) 120 ÎĐ
(c) 12 ÎĐ(d) 1.2 ÎĐ

2.3 The voltage drop across a 1.5-kW toaster that draws 12 A of current is:

(a) 18 kV(b) 125 V
(c) 120 V(d) 10.42 V

2.4 The maximum current that a 2W, 80 kÎĐ resistor can safely conduct is:

(a) 160 kA(b) 40 kA
(c) 5 mA(d) 25 ΞA

2.5 A network has 12 branches and 8 independent loops. How many nodes are there in the network?

(a) 19 (b) 17 (c) 5 (d) 4

2.6 The current I in the circuit of Fig. 2.63 is:

(a) −0.8 A(b) −0.2 A
(c) 0.2 A(d) 0.8 A

Figure 2.63

For Review Question 2.6.

2.7 The current Io of Fig. 2.64 is:

(a)

−4-4

A (b) −2-2 A (c) 44 A (d) 1616 A

Problems 65

2.8 In the circuit in Fig. 2.65, V is: (a) 30 V (b) 14 V (c) 10 V (d) 6 V